117k views
2 votes
Solve each inequality analyticaly. Support answers graphically. x^2+5x<2

User Narduk
by
7.8k points

1 Answer

6 votes

It is given that:


\begin{gathered} x^2+5x<2 \\ x^2+5x-2<0 \end{gathered}

Solve for x to get:


\begin{gathered} x^2+5x+(25)/(4)-2-(25)/(4)<0 \\ (x+(5)/(2))^2-((√(33))/(2))^2<0 \\ (x+\frac{5+\sqrt[]{33}}{2})(x+\frac{5-\sqrt[]{33}}{2})<0 \end{gathered}

The two values are less than 0 if either one of them is negative so it follows:


\begin{gathered} x+\frac{5+\sqrt[]{33}}{2}<0\text{ and }x+\frac{5-\sqrt[]{33}}{2}>0 \\ OR \\ x+\frac{5+\sqrt[]{33}}{2}>0\text{ and }x+\frac{5-\sqrt[]{33}}{2}<0 \end{gathered}

The graph is given as below:

The points are x=-5.372 and x=0.372 which is the same as:


x=-\frac{5+\sqrt[]{33}}{2}=-5.372,x=-\frac{5-\sqrt[]{33}}{2}=-0.372

Solve each inequality analyticaly. Support answers graphically. x^2+5x<2-example-1
User CargoMeister
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories