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25 votes

1mol of Ba contains

$\\ \sf\longmapsto 6.023* 10^(23)atoms$

No of moles in 17atoms

$\\ \sf\longmapsto (No\:of\:atoms)/(Avagadro\:no)$

$\\ \sf\longmapsto (17)/(6.023* 10^(23))$

$\\ \sf\longmapsto 2.82298* 10^(-23)mol$

Option 2

Jaybit answered Feb 12, 2022

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