Question

The height of trapezium is 4cm & its area is 30cm^(2). If the greater of the two parallel sides is double the smaller side find the lengths of parallel sides.

Answer 1

Let the smaller side be x cm. The greater side will be 2x cm. The height of the trapezium is given 4 cm. Now, the area of trapezium is given 30 cm^2.

The formula of area of the trapezium is given below:

`A=(1)/(2)*\text{ (sum of parallel sides)}*\text{ height}`

Substitute the given values in the formula:

`\begin{gathered} A=30 \\ \Rightarrow(1)/(2)*(2x+x)*4=30 \\ \Rightarrow2(3x)=30 \\ \Rightarrow6x=30 \\ \Rightarrow x=5 \end{gathered}`

So, the lengths of parallel sides are 5 cm and 2 x 5 = 10 cm.