The speed is given by:
![v=(d)/(t)](https://img.qammunity.org/2023/formulas/mathematics/college/7bvf02ex7prlyl84jiizv8vikm7s8zddn1.png)
in this case we know that in 12 minutes Bella rode 2 miles, then:
![\begin{gathered} v=(2)/(12) \\ v=(1)/(6) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/e4qcy7iig8gufhnl2n7jr9ks2xjcolqqt9.png)
This means that quotient between the distance and the time has to be 1/6, hence:
![\begin{gathered} (d)/(t)=(1)/(6) \\ t=6d \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/iiwwg8h900xtpjumyc5q1w7d8t83cxo0gq.png)
Therefore the relationship between the distance and time is:
![t=6d](https://img.qammunity.org/2023/formulas/physics/college/xtd2567vaxz9tsttl4alu7joe5m4lgy0gx.png)
and the answer is C