If the group has 9 people and we want to calculate how many subgroups of 3 people can be done, we have a combination of 9 choose 3.
A combination of n choose p can be calculated with the formula below:
![C(n,p)=(n!)/(p!(n-p)!)](https://img.qammunity.org/2023/formulas/mathematics/high-school/pqxkw0899nkdqbh61hjtj0nuj3cofsl7fp.png)
So, for n = 9 and p = 3, we have:
![C(9,3)=(9!)/(3!(9-3)!)=(9\cdot8\cdot7\cdot6!)/(3\cdot2\cdot6!)=84](https://img.qammunity.org/2023/formulas/mathematics/college/v18n0oljz0ggxapbct9842pr1i5im5yvo3.png)
Therefore 84 different committees can be made.