Question

If 5.25 moles of solute were added to 300. mL, what is the molarity?

Answer 1

The molarity M of a solution is the quotient between the amount of substance n and the volume V:

`M=(n)/(V)`

Substitute n=5.25 mol and V=300 mL = 0.3 L to find the molarity:

`M=\frac{5.25\text{ mol}}{0.3\text{ L}}=17.5\text{ mol/L}`