Question

How much heat in kcal must be added to 0.50 kg of water at room temperature ( 20°C) or raises temperature to( 30°C)

Answer 1

5 kcal

Explanation:

We have the following:

Mass of water = 0.5 kg

Change in temperature of water: 30° C - 20°C = 10°C

Specific heat of water = 1 kcal/kg*°C

The amount of heat added to the water is calculated as:

`\begin{gathered} H=m\cdot c_{\text{water}}\cdot\Delta T \\ \text{ replacing} \\ H=0.5\cdot1\cdot10 \\ H=5\text{ kcal} \end{gathered}`