LINE 1 : 3x + 4y = 20
rearranging : 4y = -3x + 20
y= -3/4 + 5 (y =mx + b)
therefore, m1 (slope) = -3/4
slopes of perpendicular lines are negative reciprocals of each other
m1 = -1 / m2 and m2 = -1/ m1
slope of line 2 (m2) = -1 / m1 = -1 / (-3/4) = 4/3
LINE 2 :
POINT - SLOPE FORM : y- y1 = m2 (x-x1)
point (3, -2); x1 = 3 and y1 = -2
m2 = 4/3
substituting the values in the point-slope form
y-y1 = m2 (x-x1)
y-(-2) = (4/3) (x-3)
y+2 = 4/3 (x) - 4/3(3)
y+2 = 4/3 x - 4
y = 4/3 x -4 - 2
y= 4/3 x -6
multiplying both sides of the equation by 3
3y = 4x -18
transposing,
4x-3y-18 = 0
answer: 4x - 3y -18 = 0