we have the function
![h(x)=(x-9)/(x^2-5x-24)](https://img.qammunity.org/2023/formulas/mathematics/college/ycqufydri7z6oaq87q58fkyt3qy5pxmh3e.png)
Remember that
The denominator cannot be equal to zero
so
Solve the quadratic equation
![x^2-5x-24=(x+3)(x-8)](https://img.qammunity.org/2023/formulas/mathematics/college/ua36bsigs6l1tl74c78zepibmpfqojaqmz.png)
substitute in the original function
![h(x)=(x-9)/((x+3)(x-8))](https://img.qammunity.org/2023/formulas/mathematics/college/d4fyf7u8yf227pgnmv35q79v8u9l3hky6d.png)
therefore
The domain of the given function is the interval
(-infinite,-3) U (-3,8) U (8, infinite)
The values that are not in the domain are
-3 and 8