21.5k views
4 votes
In the diagram below, AB || DEF, AE and BD intersect at C, m2B = 43°, and mZCEF = 152°.

In the diagram below, AB || DEF, AE and BD intersect at C, m2B = 43°, and mZCEF = 152°.-example-1

1 Answer

1 vote

From the picture, we have the necessary information:

The supplementary angles.

The parallels being intersected by two secant lines. And alternate interior angles are congruent under this condition.

The other angle of the triangle is then:

As a result, the angles vertical angles, therefore

< BAC = 28 (it confirms the alternate interior angle Therefore, we can write all the angles in the following drawing:

In the diagram below, AB || DEF, AE and BD intersect at C, m2B = 43°, and mZCEF = 152°.-example-1
In the diagram below, AB || DEF, AE and BD intersect at C, m2B = 43°, and mZCEF = 152°.-example-2
User Ravi Jayagopal
by
5.7k points