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A 220 m wire is cut into three pieces. The second piece is 2 times as long as the first. The third piece is 4 times as long as the second. How long is each piece?

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Answer:

The first piece = 20m

The second piece = 40m

The third pice = 8x = 160m

Step-by-step explanation:

Given:

Total length of wire = 220m

2nd piece = 2 times the 1st piece

3rd piece = 4 times the 2nd

To find:

The length of each of the piece

The wire was cut into 3:

1st piece + 2nd piece + 3rd piece = 220m

let the first length = x

2nd length = 2 (1st length) = 2(x)

2nd length = 2x

3rd length = 4(2nd piece) = 4(2x)

3rd length = 8x


\begin{gathered} x\text{ + 2x + 8x = 220} \\ simplify: \\ 11x\text{ = 220} \end{gathered}
\begin{gathered} divide\text{ both sides by 11:} \\ (11x)/(11)=(220)/(11) \\ x\text{ = 20} \end{gathered}

The first piece = 20m

The second piece = 2x = 2(20) = 40m

The third pice = 8x = 8(20) = 160m

User Keithstric
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