Answer:
3.9 degrees
Step-by-step explanation
Given the following
Altitude of the plane = 5000ft = opposite
distanace of the plane from the airport = 14miles = 73,920feet
Required
angle of depression
Using the trigonometry identity
Sin theta = opposite/hypotenuse
Sin theta = 5000/73920
sin theta = 0.06764
theta = arcsin(0.06764)
theta = 3.9 degrees
Hence the angle of depression to the nearest tenth is 3.9 degrees