Question

Mesa's population at the end of 2019 was 518,012 and its growth rate has been 1.2% each year Frank lives in Mesa and wants to track the predicted population growth over time for an experiment A. Write an equation to model the population growth of MesaB. what was the population in June of 2020?round your answer to the nearest integer C.what will the population be at the end of 2020?round your answer to the nearest integer D.what will the population be at the end of 2024?round your answer to the nearest integer

Answer 1

A) The equation to model the population growth of Mesa is

P(t) = 518,012 (1.012)ᵗ

B) Population of Mesa in June, 2020 = 521,111

C) Population of Mesa by the end of 2020 = 524,228

D) Population of Mesa by the end of 2024 = 549,848

Step-by-step explanation

Growth rate is given as

P(t) = P₀ (1 + r)ᵗ

where

P(t) = Population at any time t.

P₀ = Population at the beginning of the time period.

r = Growth rate

t = Time (measured in years)

For this question,

P₀ = 518,012

r = 1.2% = 0.012

P(t) = 518,012 (1 + 0.012)ᵗ

P(t) = 518,012 (1.012)ᵗ

B) Population of Mesa in June, 2020.

Since the population of 518,012 is for the end of 2019. By June 2020, t = 0.5

P(t) = 518,012 (1.012)ᵗ

P(t = 0.5) = 518,012 (1.012)⁰.⁵

= 518,012 (1.00598)

= 521,111

C) Population of Mesa by the end of 2020.

Starting from the end of 2019, by the end of 2020, t = 1

P(t) = 518,012 (1.012)ᵗ

P(t = 1) = 518,012 (1.012)¹

= 518,012 (1.012)

= 524,228

D) Population of Mesa by the end of 2024.

Starting from the end of 2019, by the end of 2024, t = 5

P(t) = 518,012 (1.012)ᵗ

P(t = 5) = 518,012 (1.012)⁵

= 518,012 (1.061457)

= 549,848

Hope this Helps!!!