Question

If 30.0 g of carbon dioxide is consumed what mass in grams of glucose is produced? Answer with 3 significant digits

Answer 1

21.976g of glucose are produced from 30.0g ofcarbon dioxide.

In the equation of the photosynthesis process, carbon dioxide (CO2) reacts with water (H2O) to produce glucose (C6H12O6) and oxygen (O2):

`6CO_2+6H_2O\text{ }\rightarrow C_6H_(12)O_6+6O_2`

1st) It is necessary to calculate the amount of carbon dioxide and glucose with the relation of moles in the photosynthesis equation. We can calculate that with the molar mass of carbon dioxide and the molar mass of glucose:

- Carbon dioxide molar mass: 44g/mol

Grams of CO2 in the equation:

6mol x 44g/mol = 246 g of CO2

- Glucose molar mass: 180.2g/mol

Grams of C6H12O6 in the equation:

1mol x 180.2g/mol = 180.2 g of C6H12O6

Now we know that 246g of CO2 are consumed to produce 180.2g of C6H12O6.

2nd) With the calculated values we can use a mathematical Rule of Three to calculate the grams of glucose that are produced from 30.0 of carbon dioxide:

`\begin{gathered} 246gCO_2-180.2gC_6H_(12)O_6 \\ 30.0gCO_2-x=(30.0gCO_2\cdot180.2gC_6H_(12)O_6)/(246gCO_2) \\ \\ x=21.976gC_6H_(12)O_6 \end{gathered}`

So, 21.976g of glucose are produced from 30.0g ofcarbon dioxide.