Hello there. To solve this question, we'll have to remember some properties about trapezoids.
Given a trapezoid with larger and smaller bases B and b, respectively, and height h (being the orthogonal projection of one of the bases onto another) as follows:
Its area A is given by the formula:
![A=((B+b)\cdot h)/(2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/i4hej1leb6o59wpg4o95of7x2rersvbd21.png)
In the case of the question, we have a trapezoid with bases measuring 20 cm, 6 cm and height measuring 10 cm.
Plugging the values in the formula, we get:
![A=((20+6)\cdot10)/(2)=(260)/(2)=130\text{ cm}^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/wcz76z8kgmgiggz92wtcho7o6q2gktyptz.png)
This is the area of this trapezoid.