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At the park there is a pool shaped like a circle. A ring-shaped path goes around the pool.

At the park there is a pool shaped like a circle. A ring-shaped path goes around the-example-1
User Tusk
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1 Answer

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Step 1

Find the area of the pool shaped like a circle


\begin{gathered} Area\text{ of a circle=}\pi r^2 \\ Area\text{ of the pool= Area of the inner circle - Area of outer the circle} \\ Area\text{ of the inner circle=3.14}*6^2=(2826)/(25)yd^2 \end{gathered}
Area\text{ of outer circle=3.14}*8^2=(5024)/(25)

Step 2

Area of the circular pool will be;


\begin{gathered} =(5024)/(25)-(2826)/(25) \\ =(5024-2826)/(25)=(2198)/(25)=87.92yd^2 \end{gathered}

Step 3

Find how many gallons of coating is needed


\begin{gathered} 1\text{ gallon of coating covers 8yd}^2 \\ The\text{ number of required gallons=}(87.92)/(8)=10.99\text{ gallons} \\ \approx11\text{ gallons} \end{gathered}

Answer;


Approximately\text{ 11 gallons of coating}

User Cccnrc
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