Question

3x2 + 10x - 8need to factor not sure how

Answer 1

`3x^2+10x-8`

To factor an equation in the form:

`ax^2+bx+c`

1. You can start by factor the term b as the add of two terms that multiplying give: -24

`a\cdot c=3\cdot(-8)=-24`

and the adding = 10

in this case could be 12 and -2

you get:

`3x^2+(12-2)x-8`
`3x^2+12x-2x-8`

2. You can factor then finding the greatest common denominator by grouping the first two terms and the last two:

`(3x^2+12)-2x-8`

To the first two terms you have the gratest common denominator 3x and the second gruop -2

`3x(x+4)-2(x+4)`

Then you finally factor the greatest common denominator:

The final factor is:
`(x+4)(3x-2)`