Question

7. Center on the y-axis, radius 5, x-into (d) C(2, -3), 3. x-intercept 4, y-intercept 2, passes through 5. Center on x = 3, radius V13, passes through g the given properties. (6, 5) (0, 0) ugh

Answer 1

What we have to do first is draw the cartesian plane.

We know that the center of the circle is located in x=3 the line in green and that it passes through (6,5) point A.

A circle is represented by the equation:

`\begin{gathered} (x-h)^2+(y-k)=r^2 \\ r^2=(\sqrt[]{13})^2=13 \end{gathered}`

The equation of this circle is, having the point A (6,5)

`(6-h)^2+(5-k)^2=13`

Being (h,k) the center of the circle.