Question

Three squares areJoined at the verticesto form a right triangle.The figure on the rightshows the areas of twoof the three squares,what could be the areaof the third square?A-7 inchesB-169 inchesC-49D-119

Answer 1

Answer:

169 inches²

Explanations:

The length of each side of a square = √Area

The length of each side of the first square = √144 = 12inches

The length of each side of the second square = √25 = 5 inches

Let the length of each side of the third square be l

The right-angled triangle formed by joining the vertices of the three squares is shown below:

Using the Pythagora's theorem to find the length of each side of the third square:

`\begin{gathered} l^2=12^2+5^2 \\ l^2=\text{ 144 + 25} \\ l^2=\text{ 169} \\ l\text{ = }\sqrt[]{169} \\ l\text{ = 13 inches} \end{gathered}`

The area of the third square is:

Area = l²

Area = 13²

Area = 169 inches²