Ok, here we have a right triangle so, we can use trigonometric ratios, in this case we could use the sine or the cosine since we know all the angles and a leg, and we need to find the hypotenuse. We choose to use the sine:
![\sin (45)=\frac{\sqrt[]{3}}{x}](https://img.qammunity.org/2023/formulas/mathematics/college/lmwrkxilikuiwy0q5glhx4jd9l013cqsnd.png)
![\frac{\sqrt[]{2}}{2}=\frac{\sqrt[]{3}}{x}](https://img.qammunity.org/2023/formulas/mathematics/college/s8goelr521dpsg5995mqzq8g6q28ho3uzw.png)
So, we are going to clear x:
![x=\frac{\sqrt[]{3}\cdot2}{\sqrt[]{2}}=\sqrt[]{6}](https://img.qammunity.org/2023/formulas/mathematics/college/w4ln8lazq538hl6qowinxy08ghdxv56k2d.png)