Given that the attendance to one activity is independent of attendance at the other, then:
Let Pa the joint probability of attendance to both activities of Aisha and Pb the joint probability of attendance to both activities of Pa the :
Pa = 0.90 x 0.68 = 0.61
Pb = 0.71 x 0.89 = 0.63
Then Brandon is more likely to attend both activities because Pb = 0.63 > Pa = 0.61.