The two groups of rabbits grow exponentially and linearly respectively.
For group M with an exponential growth model where the population doubles each year, we have the model to be:
![P(t)=5(2)^t](https://img.qammunity.org/2023/formulas/mathematics/college/asfbbamtak3g9v23trpzqktjw4c0c7efl4.png)
For group N with a linear model, we have the model to be:
![P(t)=10+mt](https://img.qammunity.org/2023/formulas/mathematics/college/78qndaz3n83dcbpfyc8d9yya8t6gbu8gav.png)
where m is the rate of change of the population of rabbits.
After 3 years, both populations are equal. Hence, we can put t = 3 into the equations and equate them to one another:
![5(2)^3=10+3m](https://img.qammunity.org/2023/formulas/mathematics/college/eym1dnxylg5jl6o4oa4ajg0pzop7atnpk4.png)
Solving for m, we have:
![\begin{gathered} 40=10+3m \\ 3m=40-10=30 \\ m=(30)/(3) \\ m=10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cmtecw5uac1fsnk50j6yqx7b698qnnaer1.png)
OPTION D is correct.