Question

f(x) =x2-6x+11 Find the AXIS OF SYMMETRY and VERTEX. PLACE THE VERTEX AS THE MIDDLE ROW.Number up and down, then complete the table.GRAPH!

Answer 1

Vertex is the minimum point for an upward opening parabola, if the parabola opens downward, the vertex is the maximum point. And the axis of symmetry is the line that you could reflect the parabola around and its simmetric!

So, let's start:

To calculate the vertex of a parabola, there is one simple formula:

`\begin{gathered} f(x)=x^2-6x+11 \\ -(b)/(2a)=-((-6))/(2(1))=3 \\ f(3)=(3)^2-6(3)+11 \\ f(3)=2 \\ \text{Vertex would be (3,2)} \end{gathered}`

And the axis of symmetry would be the line that you could reflect, and you use the same formula -b/2a, so the axis of symmetry would be x=3.