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How many moles of solute are required to make 3.0L of a 2.0M solution

User Iiz
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Answer:

6.0 moles.

Step-by-step explanation:

To solve this problem, we have to use the molarity formula. Remember that the molarity (M) of a solution is the number of moles of solute dissolved in one liter of solution:


Molarity\text{ \lparen M\rparen=}\frac{moles\text{ of solute}}{liter\text{s of solution}}=(mol)/(L).

We want to find 'moles of solute', so we have to solve for this unknown value and replace the given data (molarity = 2.0 M, liters of solution = 3.0 L):


\begin{gathered} Moles\text{ of solute=molarity}\cdot liters\text{ of solution,} \\ \\ Moles\text{ of solute=2.0 M}\cdot3.0\text{ L,} \\ \\ Moles\text{ of solute= 6.0 moles.} \end{gathered}

The answer would be that we require 6.0 moles to prepare the wanted solution.

User Mattrick
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