Answer:
Step-by-step explanation:
Let the initial velocity of the two moving balls be u
Let the mass of one ball be m
Let the velocity after collision be v
Initial kinetic energy is
2(½mu²) = mu²
Assuming the 35° is measured above and below a common axis,
conservation on momentum.
the vertical portion of that velocity and momentum will be equal and will cancel out.
the horizontal momentum will be
m(ucos35) + m(ucos-35) + m(0) = 3mv
v = (2/3)ucos35 = 0.5461u
final kinetic energy is
½(3m)(0.5461u²) = 0.44734mu²
so the fraction of kinetic energy converted to heat energy is
(mu² - 0.44734mu²) / mu² = 0.5526599... = 0.55