Question

Plot Points & Graph Line (Table Given)

Answer 1

Given the linear equation;

`y=(1)/(5)x+5`

The points on the graph given the x values are as follows;

`\begin{gathered} When\text{ x=4, then} \\ y=(1)/(5)(4)+5 \\ y=(4)/(5)+5 \\ y=5(4)/(5) \\ y=5.8 \\ (4,5.8) \end{gathered}`
`\begin{gathered} \text{When x=5, then} \\ y=(1)/(5)(5)+5 \\ y=1+5 \\ y=6 \\ (5,6) \end{gathered}`
`\begin{gathered} \text{When x=6} \\ y=(1)/(5)(6)+5 \\ y=(6)/(5)+5 \\ y=1(1)/(5)+5 \\ y=6(1)/(5) \\ y=6.2 \\ (6,6.2) \end{gathered}`
`\begin{gathered} \text{When x=7, then} \\ y=(1)/(5)(7)+5 \\ y=(7)/(5)+5 \\ y=1(2)/(5)+5 \\ y=6(2)/(5) \\ y=6.4 \\ (7,6.4) \end{gathered}`
`\begin{gathered} \text{When x=8, then} \\ y=(1)/(5)(8)+5 \\ y=(8)/(5)+5 \\ y=1(3)/(5)+5 \\ y=6(3)/(5) \\ y=6.6 \\ (8,6.6) \end{gathered}`
`\begin{gathered} \text{When x=9, then} \\ y=(1)/(5)x+5 \\ y=(1)/(5)(9)+5 \\ y=(9)/(5)+5 \\ y=1(4)/(5)+5 \\ y=6(4)/(5) \\ y=6.8 \\ (9,6.8) \end{gathered}`
`\begin{gathered} \text{When x=10} \\ y=(1)/(5)x+5 \\ y=(1)/(5)(10)+5 \\ y=2+5 \\ y=7 \\ (10,7) \end{gathered}`

The points on the line

`y=(1)/(5)x+5`

have been calculated above.

Two points on this line are shown below;

The attachment above shows two points which are;

`\begin{gathered} (4,5.8) \\ (10,7) \end{gathered}`