Question

According to the American automobile association 7.3% of Americans plans to travel by car over the next holiday weekend and 82.2% plans to stay-at-home what is the probability that a randomly selected American plans to stay home or travel by car over the next holiday weekend

Answer 1

Step 1: Concept

First, write the formula for probability

`\text{Probability of any event = }\frac{N\text{umber of required outcomes}}{N\text{umber of total possible outcomes}}`

Step 2: Write out the given data.

7.3% of Americans plans to travel by car over the next holiday weekend

82.2% plans to stay-at-home.

Total possible outcomes = 100%

Step 3: Final answer

A number of required outcomes = Stay at home or travel by car over the next holiday weekend

= 7.3 + 82.2

= 89.5%

`\begin{gathered} \text{Probability = }(89.5)/(100) \\ =\text{ 0.895} \end{gathered}`