226k views
5 votes
The line that contains the points (1,5) and (-3, 3). What is the equation of the line?

User Jonathon
by
8.0k points

1 Answer

2 votes

Given the following points that pass through a line:

Let,

Point A : (-3, 3)

Point B : (1, 5)

Let's determine the equation of the line in Slope-Intercept Form: y = mx + b

Step 1: Let's determine the slope of the line (m).


\text{ m = }(y_2-y_1)/(x_2-x_1)
=\text{ }\frac{5\text{ - 3}}{1\text{ - (-3)}}\text{ = }\frac{5\text{ - 3}}{1\text{ + 3}}
m\text{ = }(2)/(4)\text{ = }(1)/(2)

Step 2: Let's determine the y-intercept (b). Substitute m = 1/2 and x,y = 1,5 in y = mx + b.


\text{ y = mx + b}
\text{ 5 = (}(1)/(2))(1)\text{ + b}
5\text{ - }(1)/(2)\text{ = b}
(10)/(2)\text{ -}\frac{1}{2\text{ }}\text{ = b}
\text{ }(9)/(2)\text{ = b}

Step 3: Let's complete the equation. Substitute m = 1/2 and b = 9/2 in y = mx + b.


\text{ y = (}(1)/(2))x\text{ + (}(9)/(2))
\text{ y = }(1)/(2)x\text{ + }(9)/(2)

Therefore, the equation of the line is y = 1/2x + 9/2.

User JWCS
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories