Given:
![25m^2-10m+1](https://img.qammunity.org/2023/formulas/mathematics/college/99rm4fp8k84iuftkocb9zr73loly30wcx8.png)
Let's factor the expression.
To factor the expression, first rewrite 5² = 25:
![\begin{gathered} 5^2m^2-10m+1 \\ \\ (5m)^2-10m+1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mvh25p6wabz0lsowjgn0fiivoc5be479vv.png)
Now, rewrite 1² = 1:
![(5m)^2-10m+1^2](https://img.qammunity.org/2023/formulas/mathematics/college/82971h5xscjphr8exopcb8gjdcijgpd4iv.png)
Now, check that the middle term is two times the product of the first term being squared (5m) and the last term (1).
We have:
2 x (5m x 1) = 10 m
Thus, we have the expression:
![(5m)^2-2*5m*1+1^2](https://img.qammunity.org/2023/formulas/mathematics/college/mxo0srcbtl8wcc4v6m2c4jp8pc4rq69bh8.png)
Now, factor using the Perfect Square Trinomial rule:
![a^2-2ab+b^2=(a-b)^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/292484m0w57afgx1jmqudlw002ww1bbohy.png)
Thus, we have:
![(5m)^2-2*5m*1+1^2=(5m-1)^2](https://img.qammunity.org/2023/formulas/mathematics/college/91yok9t114ujzyqu18dbmrn4tv464ob03j.png)
Where:
• a = 5m
,
• b = 1
Therefore, the factored form of the given expression is:
![(5m-1)^2](https://img.qammunity.org/2023/formulas/mathematics/college/5hqfotn8jbjl3v83hfop3jzgjt5t8pvfby.png)
ANSWER:
![(5m-1)^2](https://img.qammunity.org/2023/formulas/mathematics/college/5hqfotn8jbjl3v83hfop3jzgjt5t8pvfby.png)