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The numbers of trading cards owned by 9 middle-school students are given below.(Note that these are already ordered from least to greatest.)346, 436, 454, 465, 483, 488, 523, 532, 647Suppose that the number 647 from this list changes to 440. Answer the following.

The numbers of trading cards owned by 9 middle-school students are given below.(Note-example-1
User Sparcut
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The mean of a set is given by the sum of all elements, dividing by the total amount of elements. If we change the number 647 from this list to 440, the amount of elements will remain the same, but the sum of all elements will decrease, therefore, the mean will decrease. Let's calculate both means to know the difference.

Mean of the set with 647:


\bar{x}=(346+436+454+465+483+488+523+532+647)/(9)=486

Mean for the set with 440 instead:


\bar{x}=(346+436+454+465+483+488+523+532+440)/(9)=463

The difference between those means is


486-463=23

The mean will decrease by 23.

In a set with an odd amount of elements, the median is the middle element. The one that stays perfectly in the middle in the set is ordered in increasing order.

In our original set, the median is


\lbrace346,436,454,465,483,488,523,532,647\rbrace

483.

If we change 647 by 440 and reorder in increasing order, the new median will be


\lbrace346,436,440,454,465,483,488,523,532\rbrace

465.

Therefore, the median will decrease by 18.

User Nihal Saxena
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