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Write an equation, for the line whose slope is -3/2 and passes through the point (4,-7).

User Waweru
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1 Answer

5 votes

The form of the equation of a line is

y = m x + b

m is the slope

b is the y-intercept

Since the slope of the line is -3/2


m=-(3)/(2)

Substitute it in the form of the equation


y=-(3)/(2)x+b

To find b substitute x and y in the equation by the coordinates of a point on the line

Since the line passes through the point (4, -7), then

x = 4 and y = -7


\begin{gathered} -7=-(3)/(2)(4)\text{ + b} \\ -7=-6+b \end{gathered}

Add 6 to both sides to find b

-7 + 6 = -6 + 6 + b

-1 = b

Substitute the value of b in the equation


\begin{gathered} y=-(3)/(2)x+(-1) \\ y=-(3)/(2)x-1 \end{gathered}

The equation of the line is y = -3/2 x - 1

User Djt
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