Question

of stion Instructions: Use the ratio of a 45-45-90 triangle to solve for the variables. Leave your answers as radicals in simplest form. m 512 n 45° N т n =

Answer 1

From the diagram, we can see that

`\begin{gathered} \sin \text{ 45 = }\frac{m}{5\sqrt[]{2}} \\ \frac{1}{\sqrt[]{2}}\text{ = }\frac{m}{5\sqrt[]{2}} \\ 1\text{ = }(m)/(5) \\ m\text{ = 1 x 5 = 5} \end{gathered}`
`\begin{gathered} \cos \text{ 45 = }\frac{n}{5\sqrt[]{2}} \\ \frac{1}{\sqrt[]{2}}\text{ = }\frac{n}{5\sqrt[]{2}} \\ 1\text{ = }(n)/(5) \\ n\text{ = 1 x 5 = 5} \end{gathered}`