You know that the Function A is:

Substitute the given value of "x" into the Function A:

Evaluating, you get:

Given the Function B shown in the table, you need to identify the Input value 9 (or the x-value) and its corresponding Output value (or y-value).
In this case, when the value of "x" is:

The value of of "y" is:

Since the Output value in Function B is less than the the Output value in Function A when the value of "x" is 9, you can determine that the the answer is: