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What is the magnitude of the electric field 12 cm from a charge of 1.5 nC?

What is the magnitude of the electric field 12 cm from a charge of 1.5 nC?-example-1

1 Answer

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Answer: b. 9.4 x 10^2 N/C

Step-by-step explanation:

The formula for calculating electric field strength, E at a point, X a distance of d from a charge is expressed as

E = kq/d^2

where

k is the electrostatic constant and its value is 9 x 10^9 N/m^2C^2

q is the magnitude of the charge in coulombs

From the information given

q = 1.5 nC

Recall,

1 nC = 1 x 10^- 9 C

1.5 nC = 1.5 x 1 x 10^- 9 = 1.5 x 10^-9 C

q = 1.5 x 10^-9 C

d = 12 cm

We would convert 12 cm to meters

Recall, 100 cm = 1m

12 cm = 12/100 = 0.12 m

d = 0.12 m

By substituting these values into the formula,

E = (9 x 10^9 x 1.5 x 10^-9)/0.12^2

E = 937.5

Rounding to the nearest ten, it becomes

E = 940 = 9.4 x 10^2

The answer is

b. 9.4 x 10^2 N/C

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