Answer:
![A\text{ : }(2)/(13)](https://img.qammunity.org/2023/formulas/mathematics/college/aisrsxha8ldat0ig730b1ryc2ny04nibcm.png)
Step-by-step explanation:
Here, we want to get the probability of drawing an ace or a 6 from a deck of 52 cards
There are 4 suites in a deck and each deck has a 6. Thus, there are 4 6s
Each suite has an ace and thus, there are 4 aces
The probability of drawing a specific item is the number of items divided by the total number of items
The probability of drawing an ace will be:
![(4)/(52)](https://img.qammunity.org/2023/formulas/mathematics/high-school/3eu13lc0s2x3f1bwwekkjwz3oacwk9e4po.png)
The probability of drawing a 6 will be:
![(4)/(52)](https://img.qammunity.org/2023/formulas/mathematics/high-school/3eu13lc0s2x3f1bwwekkjwz3oacwk9e4po.png)
Now,the probability of drawing an ace or a 6 will be the sum of these two
Mathematically, we have this as:
![(4)/(52)+\text{ }(4)/(52)\text{ }=\text{ }(8)/(52)\text{ = }(2)/(13)](https://img.qammunity.org/2023/formulas/mathematics/college/bs0ck0if7uhjplya241k1yixe9tlan2vd3.png)