Question

The perimeter of a rectangle is 72 meters. The width of

the rectangle iS 4 meters less than its length. Find the length and the
width of the rectangle. What is the equation

Answer 1

Length = 20 feet

Width = 16 feet

Explanation:

Given information:

• The perimeter of a rectangle is 72 meters.
• The width of the rectangle is 4 meters less than its length.

Define the variables:

• Width = x meters
• Length = (x + 4) meters

Substitute the defined variables and given perimeter into the formula for the perimeter of a rectangle.

`\begin{aligned}\textsf{Perimeter of a rectangle}&=2(\sf width+length)\\\\\implies 72&=2(x+(x+4))\\72&=2(2x+4)\\72&=4x+8\\64&=4x\\x&=16\end{aligned}`

Therefore the dimensions of the rectangle are:

• Length = 16 + 4 = 20 feet
• Width = 16 feet