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Find the equation of the line that passes through the given point and has the given slope. (Use x as your variable.)(4, −3), m = −2

User Love Gupta
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General equation of line:


y=mx+c

Where,


\begin{gathered} m=\text{slope} \\ c=y-\text{intercept} \\ (x,y)=(4,-3) \end{gathered}

Slope of line is -2 then:


\begin{gathered} y=mx+c \\ y=-2x+c \end{gathered}
(x,y)=(4,-3)
\begin{gathered} y=-2x+c \\ -3=-2(4)+c \\ -3=-8+c \\ 8-3=c \\ 5=c \end{gathered}
\begin{gathered} y=mx+c \\ y=-2x+5 \end{gathered}

Equation of line is y=-2x+5

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