Question

What's the perimeter of 3x2-1x2-4x+3 for parallelogram?

Answer 1

The perimeter of the parallelogram is;

`8x^2-8x+4`

Step-by-step explanation:

Given the figure of a parallelogram in the attached image.

With sides;

`\begin{gathered} a=x^2-4x+3 \\ b=3x^2-1 \end{gathered}`

The perimeter of a parallelogram can be calculated using the formula;

`P=2(a+b)`

substituting the given sides;

`\begin{gathered} P=2(a+b) \\ P=2(x^2-4x+3+3x^2-1) \\ P=2(x^2+3x^2-4x+3-1) \\ P=2(4x^2-4x+2) \\ P=8x^2-8x+4 \end{gathered}`

Therefore, the perimeter of the parallelogram is;

`8x^2-8x+4`