The equation of a circle is given by:
![\lparen x-h)\placeholder{⬚}^2+\left(y-k\right)^2=r^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/7jxvihmka4nzvccc2lmpcleh8pstyyymds.png)
where (h,k) is the center and r is the radius.
In this case we know that the center of the circle is (-4,3). To find the radius we just need to remember that the radius is half the diameter, hence:
![r=(9)/(2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/5otbwpk1tvn53pjlqipyr1eisceu0x7hsv.png)
Plugging the values for the center and the radius we have that:
![\begin{gathered} \lparen x-\left(-4\right))\placeholder{⬚}^2+\left(y-3\right)^2=\lparen(9)/(2))^2 \\ \lparen x+4)\placeholder{⬚}^2+\left(y-3\right)^2=(81)/(4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ddgpk5mx7jbeeochkoturtjybqiziuhehz.png)
Therefore, the equation of the circle is:
![\operatorname{\lparen}x+4)\placeholder{⬚}^2+\left(y-3\right)^2=(81)/(4)]()