Question

A couple has two children. Let A be the event that their first child is a boy, and note that P(A) = 51.2%. Let B be theevent that their second child is a girl, with P(B) = 48.8%.A and B are independent events. What is the probability that the couple has a first child that is a boy and a second childthat is a girl?Give your answer as a decimal rounded to two decimal places.

Answer 1

P(A and B) = 0.25

Step-by-step explanation:

Since P(A) and P(B) are independents events, The probability P(A) and P(B) occurs consecutively is P(A)*P(B):

P(A and B) = P(A)*P(B)

P(A and B) = 0.512*0.488

P(A and B) = 0.25