Question

Suppose f(x) = 3x² – 48. Solve f(x) = 0

Answer 1

x = 4 and x = -4

Explanation:

We have the following function:

`f(x)\: =\: 3x^(2)\: -\: 48`

We solve the values of x for when the function is equal to 0, as follows:

`\begin{gathered} \: 3x^(2)\: -\: 48=0 \\ \: 3x^(2)\: -=48 \\ x^2=(48)/(3) \\ x=\sqrt[]{16} \\ x=\pm4 \end{gathered}`