Question

A sample of gas is being held at a pressure of 1520 Torr, has a volume of 60.0 L and a temperature of 202 K. If the conditions are changed toSTP, what is the new volume of the gas?

Answer 1

The new volume of the gas is 162.28L

Step-by-step explanation

Given that;

The initial temperature of the gas is 202K

The initial pressure of the gas is 1520 torr

The initial volume of the gas is 60.0L

The final temperature of the gas at STP is 273.15K

The final pressure of the gas at STP is 760 torr

Follow the steps below to find the final volume of the gas

Step 1; Write the general gas law equation

`\text{ }\frac{\text{ P1V1}}{\text{ T1}}\text{ = }\frac{\text{ P2 V2}}{\text{ T2}}`

Step 2; Substitute the given data into the equation above to find the final volume of the gas

`\begin{gathered} \text{ }\frac{\text{ 1520 }*\text{ 60}}{202}\text{ }=\frac{\text{ 760 }*\text{ V2}}{\text{ 273.15}} \\ \text{ cross multiply} \\ \text{ 1520 }*\text{ 60 }*\text{ 273.15 }=\text{ 760 }*\text{ V2 }*\text{ 202} \\ \text{ 24,911,280 = 153,520V2} \\ \text{ Divide both sides by 153, 520} \\ \text{ }\frac{24,911,280}{153,\text{ 520}}\text{ = }\frac{\cancel{153,520}V2}{\cancel{153,520}} \\ \text{ V2 = 162.28L} \end{gathered}`

Therefore, the new volume of the gas is 162.28L