Question

If a car sped around a curve in the road and experienced a centripetal acceleration of 6.7 m/ s 2 if the radius of the curve in the road was 70 m, what was the car’s tangential velocity?

Answer 1

Givens,

• Centripetal acceleration = 6.7 m/s^2.

,

• Radius = 70 m.

The formula to find the tangential velocity is

`a_(cp)=(v^2)/(r)`

Where a = 6.7 m/s^2 and r = 70 m. Solve for v.

`\begin{gathered} 6.7\cdot(m)/(s^2)=(v^2)/(70m) \\ v^2=70m\cdot6.7\cdot(m)/(s^2) \\ v=\sqrt[]{469\cdot(m^2)/(s^2)} \\ v\approx21.66\cdot(m)/(s) \end{gathered}`

Therefore, the tangential velocity is 21.66 m/s.