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Triangles ACD and BCD are isosceles. Angle BAC has a measure of 17degrees and angle BDC has a measure of 52 degrees. The measure ofangle ABD is degrees.

Triangles ACD and BCD are isosceles. Angle BAC has a measure of 17degrees and angle-example-1

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Step-by-step explanation

We want to find the measure of We are given that:


\begin{gathered} <\text{BAC}=17\degree \\ <\text{BDC}=52\degree \end{gathered}

Triangle BDC is an isosceles triangle. This means that:


<\text{BDC}=<\text{BCD}

We need to find the measure of apply the sum of angles in a triangle:


\begin{gathered} <\text{BDC}+<\text{BCD}+<\text{CBD}=180 \\ \Rightarrow52+52+<\text{CBD}=180 \\ 104+<\text{CBD}=180 \\ \Rightarrow<\text{CBD}=180-104 \\ <\text{CBD}=76\degree \end{gathered}

From the figure, we see that triangle ABC and ABD are congruent triangles. This means that all three sets of angles in the triangles are congruent (equal in measure).

Therefore:


<\text{ABC}=<\text{ABD}

The sum of angles at a point is equal to 360 degrees. This means that:


<\text{ABC}+<\text{ABD}+<\text{CBD}=180

Since angles
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