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7 votes
7 votes
This circle is centered at the point (3,2) and the length of its radius is 5 what is the equation of the circle

User Daniel Winterstein
by
2.8k points

2 Answers

20 votes
20 votes

Answer:

(x - 3)² + (y - 2)² = 25

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Here (h, k ) = (3, 2 ) and r = 5 , then

(x - 3)² + (y - 2)² = 5² , that is

(x - 3)² + (y - 2)² = 25 ← equation of circle

User Bengerman
by
3.3k points
24 votes
24 votes

Answer:(x-3)² + (y-2)² = 25

Step-by-step explanation:

A circle's equation is (x-h)² + (y-k)² = r². When centered at the origin, h and k equal 0. If you shift the circle, say, one unit up, then k equals 1, and the equation is x² + (y-1)² = r².

So for your circle, the equation would be (x-3)² + (y-2)² = 5² or (x-3)² + (y-2)² = 25.

User ThreeFx
by
2.5k points
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