Question

The length of a rectangle is 5 more than twice its width. its perimeter is 70 cm. what is its area? show your solution

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Answer 1

let

b=x then'

l= 2x+5

Now

p=70

2(l+b)=70

2(x+2x+5)=70

6x+10=70

6x=60

x=6

b=x=10

l=2x+5=25

area of rectangle = l*b

25*10

=250 answer

Answer 2

`250cm^2`

Explanation:

length = 5 + 2w

width = w

P = Sum of all sides

P = 2 * (5 + 2w) + 2w

P = 10 + 4w + 2w

P = 6w + 10

Given Perimeter = 70cm

We substitute

6w + 10 = 70

6w = 70 - 10

6w = 60

w = 60/6

w = 10cm

Since length is 5 + 2w

length = 5 + (2 * 10)

length = 25cm

Area = lw

Area = 25 * 10

Area =
`250cm^2`