Question

I need help with these two questions 100 points 50 points per question

Answer 1

Let us write out the formula for discriminant,

`D=b^2-4ac`

Let us write out the general quadratic equation,

`ax^2+bx+c=0`

Let us write out the given equation,

`x^2+11x-10=0`

Comparing the two equations, and getting the values for a, b and c.

`\begin{gathered} a=1 \\ b=11 \\ c=-10 \end{gathered}`

Let us now solve for the discriminant,

`\begin{gathered} D=11^2-4(1)(-10) \\ D=121+40 \\ D=161 \end{gathered}`

Since the discriminant is positive, the quadratic has two real solutions.