Question

Oliver estimates the weight of his cat to be 16 pounds. The actual weight of his catis 14.25 pounds. What is the percent error of Olivers estimate Round the percent to the nearest tenth if necessary

Answer 1

Given :

The estimated weight of the cat = 16 pounds

The actual weight of the cat = 14.25 pound

The error = the difference of weight = 16 - 14.25 = 1.75 pounds

The percentage error =

`(1.75)/(14.25)\cdot100=0.1228\cdot100=12.28\%`

Rounding to the nearest tenth

So, the percentage error = 12.3 %