Question

Question:A 1.5 kg mass is traveling to the left at 6.0 m/s. It then experiences an impulse represented in the F vs T graph. Find the following1) What is the total impulse given to the ball?2) What is the change in momentum of the ball?3) What is the final velocity of the ball?

Answer 1

(1) 20 N*s

(2) 20 N*s

(3) 19.3 m/s

Step-by-step explanation

The impulse experienced by an object equals the change of momentum of the object. From the F-t graph, the change in momentum is the area under the curve. The curve shown is a trapezium, so the area is,

`J=\Delta p=(1)/(2)h(B+b)=(1)/(2)\cdot50N\cdot(0.3+0.5)s=20N\cdot s`

The impulse or change in momentum of an object is given by,

`\Delta p=m\cdot\Delta v=m\cdot(v_f-v_i)`

Solving for vf,

`v_f=(\Delta p)/(m)+v_i`

The impulse, as found before, is 20N*s, the mass of the ball is 1.5kg and the initial velocity is 6m/s,

`v_f=(20N\cdot s)/(1.5kg)+6m/s\approx19.3m/s`