Let's find the equation of the circle using the general equation for the circle:

where ( h, k ) is the center and r is the radius.
we know the center which is (6,-3), so:

Also, we know one of the points of the circle, so:
![\begin{gathered} (-6,2) \\ (-6-6)^2+(2+3)^2=r^2 \\ (-12)^2+(5)^2=r^2 \\ 144+25=r^2 \\ so\colon \\ r^2=169 \\ r=\sqrt[]{169} \\ r=13 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zgyvva265d70hdpzoj905bfy3mbw1teop4.png)
Since we know the radius of the circle, we can find the area easily with the following formula:
